Question
A sum of Rs. 20000 is invested for three years at
compound interest. The rate of interest for first year is 20 percent per annum, for second year it is 15 percent per annum and for third years it is 10 percent per annum. Find the interest for the third year.Solution
For 1st year, R% = 20% Amount = 20000 × [(1 + (20/100)] => 20000 × [1 + (1/5)] => 20000 × (6/5) = 24000 Compound Interest = 24000 – 20000 = Rs.4000 For 2nd year, P = Rs.24000 and R% = 15% Amount = 24000 × [(1 + (15/100)] => Amount = 24000 × (23/20) = 1200 × 23 = Rs.27600 Compound Interest = 27600 – 24000 = Rs.3600 For 3rd year, P = Rs. 27600, R% = 10%, Amount = 27600 × [(1 + (10/100)] = 27600 × (11/10) = 2760 × 11 = Rs. 30360 Compound Interest = 30360 – 27600 = Rs.2760
26% of 950 + 50/3% of 7962 = ? Â
- What will come in place of (?) in the given expression.
(84 + 36 ÷ 6) × 2 = ? 690 ÷ (75% of 460) = ? ÷ (50% of 160)
21% of 400 − 150 = ? − 77
Evaluate: 320 − {18 + 4 × (21 − 9)}
What will come in the place of question mark (?) in the given expression?
(50 × 6 ÷ 12) × 9 = ?
(24% of 500 - 20) ÷ 25 = ? ÷ 4
√ (12+√ (12+√ (12+ ⋯ ∞ ))Â
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