Question
A sum of Rs. 20000 is invested for three years at
compound interest. The rate of interest for first year is 20 percent per annum, for second year it is 15 percent per annum and for third years it is 10 percent per annum. Find the interest for the third year.Solution
For 1st year, R% = 20% Amount = 20000 × [(1 + (20/100)] => 20000 × [1 + (1/5)] => 20000 × (6/5) = 24000 Compound Interest = 24000 – 20000 = Rs.4000 For 2nd year, P = Rs.24000 and R% = 15% Amount = 24000 × [(1 + (15/100)] => Amount = 24000 × (23/20) = 1200 × 23 = Rs.27600 Compound Interest = 27600 – 24000 = Rs.3600 For 3rd year, P = Rs. 27600, R% = 10%, Amount = 27600 × [(1 + (10/100)] = 27600 × (11/10) = 2760 × 11 = Rs. 30360 Compound Interest = 30360 – 27600 = Rs.2760
In BGP path selection, which attribute is considered first?
Which of the following shows the count of arguments passed to the script?
Which component is responsible for translating virtual addresses to physical addresses?
Which keyword is used to throw an exception explicitly?
What is the purpose of the Program Counter (PC) in CPU control design?
Which of the following is a characteristic of a public blockchain?
In public key cryptography, which key is used for encryption?
State true or false.
Is it possible that the assignment of observations to clusters does not change between successive iterations in K-Means?
What does HTML stand for in web technology?
Which type of memory can be both read from and written to by the processor?
Relevant for Exams:
