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Taking LCM of 5, 6 and 8 = 120 units Efficiency of A = 120/5 = 24 Efficiency of B = 120/6 = 20 Efficiency of C = 120/8 = 15 Time by which all complete the work together = 120/(24 + 20 + 15) = 120/59 mins Work completed in 1 min = 59/120 Then, work completed in 1 hour = 59 × 60/120 = 59/2 Average work completed per hour per worker = (59/2) ÷ 3 = 59/6 ∴ The required average is 59/6.
Study the given arrangement carefully and answer the question that follows.
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