Question
A circular swimming pool is surrounded by a circular
path which is 4 m wide. If the area of the path is 44% of the area of the swimming pool, then the radius (in metres) of the pool will be:Solution
Area of a circle = Οr2 Let radius of circular pool be βaβ meter Given, Radius of circular path = a + 4 Area of a circular pool = Οa2 Area of a pool + circular path = Ο(a + 4)2 Given, β Ο(a + 4)2 β Οa2 = 40% Γ Οa2 β Ο(a + 4)2 β Οa2 = 11/25 Γ Οa2 β a2 + 8a + 16 β a2 = 11a2 /25 β 11a2 β 200a β 400 = 0 β 11a2 β 220a + 20a β 400 = 0 β 11a(a β 20) + 20(a β 20) = 0 β a = -20/11 or a = 20 β΄ Radius of a pool is 20 m.
1885 Γ· 64.98 + 7.29 + ? = 69.09
212 + 14 Γ 23 β 28 Γ 15 = ? Β
(22Β² Γ 8Β²) Γ· (92.4 Γ· 4.2) =? Γ 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 Γ· 22p + 1 = 43Β
What will come in place of (?) in the given expression.
(15) Β² - (13) Β² = ?? = 6.25% of 240 + 25 2 + 17 2 β 16 Γ 17
35% of 840 + 162Β = ? β 25% Γ 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 Γ· 16 + 800 Γ· β64 + ? = 200 * 2