Question
An article is marked x% (40 < x > 0) above its cost
price. It is sold by giving x/2% discount on its marked price. If there is a profit of 10(1/2) %, then what is the value of x?Solution
Marked Price (MP): M = C (1 + x/100) Selling Price (SP) with discount%: SP = M (1 - x/200) Profit of 10%: SP = C ×1.105 ATQ- C × 1.105 = C (1 + x/100) (1 - x/200) 1.105 = (1 + x/100) (1 - x/200) 1.105 = 1 + x/200 - (x 2)/20000 0.105 = x/200 - (x2)/20000 2100= 100x - x 2 x2 - 100x + 2100 = 0 x2 - 70x-30x + 2100 =0 x(x-70)-30(x-70) =0 x=30 and 70 Since x must be more than 40 x=70
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?