Question
Vikas increases his speed to (8/5) times of his original
speed and reaches his school 30 min before the usual time. Find the usual time taken by him to reach the school.Solution
Let the speed of the boy be V and time taken by the boy to reach his school be T. Speed of the boy after increase = 8/5 V Time taken by the boy to reach his school after increase in speed = T – 30 Since distance is same for both cases. ∴ Distance = VT = 8/5 V (T – 30) 8/5 T – T = 48 T = 48 × 5/3 = 80 minutes
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