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We know, (a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) Or, (21)2 = 21 + 2(ab + bc + ca) Or, 441 = 21 + 2(ab + bc + ca) Or, ab + bc + ca = (441 – 21) ÷ 2 = 210