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Sohit was born two years ago when Rohit was two years old. 2 years before the age of Rohit = 2 years Present The age of Sohit = 2 years Rohit = (2 + 2) = 4years Let the age of Mohit = x years Purohit = y years The average age of Rohit, Sohit, Mohit and Purohit (2 + 4 + x + y)/4 We will check all options for x and y average should be perfect square 8 and 2 (2 + 4 + 8 + 2)/4 = (16/4) = 4 or (2)2 = 4 We get 4 as an average which is a perfect square but the difference between the ages of any two persons is not more than five years (8-2=6) so this could not be correct answer (ii) 7 and 3 7-3 =4 Difference between two ages is not more than 5 (2 + 4 + 7 + 3)/4 = (16/4) = 4 The answer is 7 and 3
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