Sohit was born two years ago, when Rohit was two years old. At present, the average age (in years) of Sohit, Rohit, Mohit and Purohit is a perfect square. Also the difference between the ages of any two persons is not more than five years. Which of the following could be the ages of Mohit and Purohit (in years)

Sohit was born two years ago when Rohit was two years old. 2 years before the age of Rohit = 2 years Present The age of Sohit = 2 years Rohit = (2 + 2) = 4years Let the age of Mohit = x years Purohit = y years The average age of Rohit, Sohit, Mohit and Purohit (2 + 4 + x + y)/4 We will check all options for x and y average should be perfect square 8 and 2 (2 + 4 + 8 + 2)/4 = (16/4) = 4 or (2)² = 4 We get 4 as an average which is a perfect square but the difference between the ages of any two persons is not more than five years (8-2=6) so this could not be correct answer (ii) 7 and 3 7-3 =4 Difference between two ages is not more than 5 (2 + 4 + 7 + 3)/4 = (16/4) = 4 The answer is 7 and 3