Question
A rhombus has side 13 cm and one diagonal 24 cm. Find
its area.Solution
ATQ, Diagonals of a rhombus bisect each other at right angles. Half of one diagonal = 24/2 = 12 cm Let half of other diagonal = x Using Pythagoras in one of the right triangles: 12^2 + x^2 = 13^2 144 + x^2 = 169 x^2 = 25 x = 5 So second diagonal = 10 cm Area of rhombus = (1/2) x d1 x d2 = (1/2) x 24 x 10 = 120 sq cm
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