Question
The sum of interior angles of a polygon is 1,620°.
(a) Find the number of sides of the polygon. (b) Find the number of diagonals of this polygon.Solution
Sum of interior angles of n-gon: (n − 2)×180° So: (n − 2)×180 = 1620 n − 2 = 1620/180 = 9 n = 11 (b) Number of diagonals = n(n − 3)/2 = 11×8 / 2 = 44.
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