Question
Pipe 'R' and 'S' can fill a tank in 40 minutes and 1
hour respectively. 'R' is opened alone. After 16 minutes, 'R' is closed and 'S' is opened. Find the time taken by 'S' to fill the remaining tank.Solution
Let the total capacity of tank be 120 litres (LCM of 40 and 60) Efficiency of 'R' = (120/40) = 3 litres/minute Efficiency of 'S' = (120/60) = 2 litres/minute Tank filled by 'R' = 3 × 16 = 48 litres Remaining part of the tank = 120 − 48 = 72 litres Required time = (72/2) = 36 minutes
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