Question
βPβ and βQβ can do a piece of work in 12 days
and 18 days, respectively. βPβ started working alone and was replaced by βQβ after 4 days. In how many days can βQβ complete the remaining amount of work alone?Solution
Let the total work be 36 units (LCM of 12 and 18) Efficiency of βPβ = 36/12 = 3 units/day Efficiency of βQβ = 36/18 = 2 units/day Let the number of days taken by βQβ to finish the remaining amount of work be βxβ ATQ, (3 Γ 4) + 2x = 36 Or, 2x = 36 β 12 Or, 2x = 24 Or, x = 24/2 = 12 Therefore, time taken by βQβ to complete the remaining work alone = 12 days
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