Question
Pipe 'A' takes 20 minutes to fill half of the tank. Pipe
'B' is twice as efficient as pipe 'A'. Find the percentage of the tank filled by both in 8 minutes.Solution
Time taken by pipe 'A' alone to fill the entire tank = 20 × 2 = 40 minutes Let efficiency of pipe 'A' = x units/minute Tank capacity = 40x units Pipe 'B' efficiency = 2x units/minute Work in 8 minutes = (x + 2x) × 8 = 24x units Percentage filled = (24x / 40x) × 100 = 60%
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