Question
Pipe A and Pipe B together can fill the tank in 15
hours. The capacity of the pipe A is 30% of the capacity of the pipe B. How much time will pipe B alone take to fill the tank.Solution
Capacity of the pipe A = 30/100 × Pipe B Pipe A /Pipe B = 3/10 Efficiency of pipe A = 3 units Efficiency of pipe B = 10 units Total work = 15 × (3+10) = 195 units Time taken by Pipe B to fill the tank = 195/10 = 19.5 hours
16Â Â Â 48Â Â Â Â 120Â Â Â Â 240Â Â Â 360Â Â Â ?
23   27    54    ?       195    231
...130 114 106 102 100 ?
5, 11, 32, 65, ?, 389
7Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 26Â Â Â Â Â Â Â Â Â Â Â 63Â Â Â Â Â Â Â Â Â Â Â 126Â Â Â Â Â Â Â Â Â Â 215Â Â Â Â Â Â 342
...11, 9, 15, 41 ,157, 789
5 14 56 220 1125 6786
...12                          13                         30                     �...
80, 255, 624, ?, 2400, 4095
If   20       x      46      147       604        3045
Then, x% of 25 = ?
...
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