Question
Tap A can fill a tank in 10 hours. Tap B can fill 12.5%
part of the same tank in 5 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 2/5 part of the tank is filled in 8 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?Solution
Tap A alone can fill the tank in = 10 hours. Tap B alone can fill the tank in = (8/1) × 5 = 40 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 8 × (5/2) = 20 Taking LCM of 10, 40 and 20 = 40 Efficiency of Tap A = 4 Efficiency of Tap B = 1 Efficiency of Taps (A + B +C) = 2 Efficiency of Taps (A +C) = 2 – 1 = 1 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (40/1) = 10 hours
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)
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