Question
Tap A can fill a tank in 10 hours. Tap B can fill 12.5%
part of the same tank in 5 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 2/5 part of the tank is filled in 8 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?Solution
Tap A alone can fill the tank in = 10 hours. Tap B alone can fill the tank in = (8/1) × 5 = 40 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 8 × (5/2) = 20 Taking LCM of 10, 40 and 20 = 40 Efficiency of Tap A = 4 Efficiency of Tap B = 1 Efficiency of Taps (A + B +C) = 2 Efficiency of Taps (A +C) = 2 – 1 = 1 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (40/1) = 10 hours
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