📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      Tap A can fill a tank in 10 hours. Tap B can fill 12.5%

      part of the same tank in 2 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 3/7 part of the tank is filled in 6 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?
      A 20 hours Correct Answer Incorrect Answer
      B 16 hours Correct Answer Incorrect Answer
      C 28 hours Correct Answer Incorrect Answer
      D 19 hours Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

       Tap A alone can fill the tank in = 10 hours. Tap B alone can fill the tank in = (8/1) × 2 = 16 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 6 × (7/3) = 14 Taking LCM of 10, 16 and 14 = 560 Efficiency of Tap A = 56 Efficiency of Tap B = 35 Efficiency of Taps (A + B +C) = 40 Efficiency of Taps (A +C) = 40 – 35 = 5 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (560/5) = 28 hours

      Practice Next
      More Pipes and cisterns Questions

      Relevant for Exams:

      ask-question