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    Question

    Tap A can fill a tank in 10 hours. Tap B can fill 12.5%

    part of the same tank in 2 hours, whereas Tap C can alone empty a tank in ‘x’ hours. 3/7 part of the tank is filled in 6 hours, when all three taps are opened together. How much time (in hours) will Tap A and C together will take to fill 25% part of the tank?
    A 20 hours Correct Answer Incorrect Answer
    B 16 hours Correct Answer Incorrect Answer
    C 28 hours Correct Answer Incorrect Answer
    D 19 hours Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

     Tap A alone can fill the tank in = 10 hours. Tap B alone can fill the tank in = (8/1) × 2 = 16 hours Tap C alone can empty the tank in = x hours (A + B +C) together can fill the tank in = 6 × (7/3) = 14 Taking LCM of 10, 16 and 14 = 560 Efficiency of Tap A = 56 Efficiency of Tap B = 35 Efficiency of Taps (A + B +C) = 40 Efficiency of Taps (A +C) = 40 – 35 = 5 Tap A and C together take to fill 25% part of the tank in, => (25/100) × (560/5) = 28 hours

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