Question
Tap ‘A’ and tap ‘B’ can fill a tank in 45 hours
and 40 hours, respectively. If both taps are opened together, then find the time after which tap ‘A’ must be closed so the whole tank can be filled in 24 hours.Solution
Let total capacity of the tank is 360 litres (LCM of 45 and 40) Quantity of water filled by tap ‘A’ in one hour = 360/45 = 8 litres Quantity of water filled by tap ‘B’ in one hour = 360/40 = 9 litres Let tap ‘A’ is closed after ‘x’ hours So, 17 × x + 9 × (24 – x) = 360 Or, 8x = 144 Or, x = 18 hours
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 11.99 × 24.07
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
78% of 1450 + 26² = ? + 1323 ÷ 17
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...