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    Question

    In what time would a Cistern be filled by three pipes

    whose diameter are 2cm, 8/3cm and 4cm running together, where the largest pipe alone fill it in 183 minutes. The amount of water flowing in by each pipe being directly proportional to the square of diameter?
    A 72 minutes Correct Answer Incorrect Answer
    B 110 minutes Correct Answer Incorrect Answer
    C 140 minutes Correct Answer Incorrect Answer
    D 206 minutes Correct Answer Incorrect Answer
    E 108 minutes Correct Answer Incorrect Answer

    Solution

    1st Pipe 2nd Pipe 3rd Pipe Diameter 2 8/3 4 6 8 12 3 : 4 : 6 Efficiency proportional to the Square of the diameter 9 : 16 : 36 Total efficiency = 9 + 16 + 36 = 61 Pipe 3rd can fill the cistern in 183 minutes (given) Therefore, the capacity of the Tank = (36 × 183) = 6588 Now, the Time taken by all pipes together = 6588/61 = 108 minutes

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