Question
Among 5 distinct toys, how many arrangements are
possible such that 3 specific toys do not appear together?Solution
Total = 5! = 120
Together: Treat 3 toys as block + 2 others = 3! = 6
Internal = 3! = 6
Together = 6 * 6 = 36
Required = 120 - 36 = 84
Tree : Shrub :: Mountain : ?
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World : Nation :: House : (?)
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