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      Question

      Among 5 distinct toys, how many arrangements are

      possible such that 3 specific toys do not appear together?
      A 60 Correct Answer Incorrect Answer
      B 84 Correct Answer Incorrect Answer
      C 72 Correct Answer Incorrect Answer
      D 36 Correct Answer Incorrect Answer

      Solution

      Total = 5! = 120
      Together: Treat 3 toys as block + 2 others = 3! = 6
      Internal = 3! = 6
      Together = 6 * 6 = 36
      Required = 120 - 36 = 84

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