How many five digit numbers can be formed using the digits 0, 1, 2, 3, 4 and 5 which are divisible by 5, without repeating the digits?
CASE 1: If last digit is 0, number of 5 digit can be formed by using the 1, 2,3,4& 5 = 5× 4×3×2 = 120 CASE 2: If last digit is 5, number of 5 digit can be formed by using the 0, 1, 2, 3 & 4 = 4× 4×3×2 = 96 (as a number can never start with 0) So total number of digits = 120 + 96 = 216
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A number is such that when it is multiplied by 5, it gives another number which is as much above from 270 as the original number (itself) is below 270. ...
