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      Question

      The sum of the incomes of A and B is Rs. 1,00,000. A

      spends 60% of his income while B spends 80% of his income such that the savings of B is Rs. 4,000 less than that of A. If the income of C is 20% more than average savings of A and B together, then find the savings of C, given that C saves 25% of his income.
      A Rs. 3,600 Correct Answer Incorrect Answer
      B Rs. 4,200 Correct Answer Incorrect Answer
      C Rs. 4,500 Correct Answer Incorrect Answer
      D Rs. 5,000 Correct Answer Incorrect Answer
      E Rs. 5,400 Correct Answer Incorrect Answer

      Solution

      Let the income of B be Rs. ‘x’ Therefore, income of A = Rs. (100000 – x) Savings of A = 0.4 × (100000 – x) = Rs. (40000 – 0.4x) Savings of B = Rs. 0.2x According to the question, 40000 – 0.4x = 0.2x + 4000 Or, 0.6x = 36000 Or, x = 60000 Savings of A = 40000 – 24000 = Rs. 16000 Savings of B = 12000 Income of C = 1.2 × {(16000 + 12000)/2}
      = Rs. 16800 Savings of C = 0.25 × 16800 = Rs. 4200

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