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    Question

    The population of a town increases by 10% in the first

    year and by 20% in the second year. If the population at the end of the second year is 39,600, find the population at the beginning of the first year.
    A 40,700 Correct Answer Incorrect Answer
    B 30,000 Correct Answer Incorrect Answer
    C 39,500 Correct Answer Incorrect Answer
    D 30,700 Correct Answer Incorrect Answer

    Solution

    Let initial population = P. After first year (10% increase): = P Γ— 110/100 = 11P/10 After second year (20% increase): = (11P/10) Γ— 120/100 = 11P/10 Γ— 6/5 = 66P/50 = 33P/25 Given 33P/25 = 39,600 β‡’ 33P = 39,600 Γ— 25 39,600 Γ— 25 = 39,600 Γ— (100/4) = 3,960,000 / 4 = 990,000 So 33P = 990,000 P = 990,000 / 33 = 30,000

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