Question
‘S’ has 20% fewer books than ‘T’. ‘T’ has 25%
more books than ‘U’. By how much percent are the books with ‘S’ less than those with ‘U’?Solution
ATQ,
Let, number of books with ‘T’ = 25b
Number of books with ‘S’ = 0.8 × 25b = 20b
Number of books with ‘U’ = (25b/1.25) = 20b
So, required percentage = {(20b – 20b)/20b} × 100 = 0%
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