Question
20% of ‘m’ added to 80% of ‘n’ equals 160. If
‘n’ exceeds ‘m’ by 60, find the value of (2m – n).Solution
ATQ,
Given: 0.2m + 0.8n = 160 n = m + 60 Substitute n = m + 60 into the first equation: 0.2m + 0.8(m + 60) = 160 0.2m + 0.8m + 48 = 160 m + 48 = 160 m = 112 Now, n = 112 + 60 = 172 Therefore, 2m – n = (2 × 112) – 172 = 224 – 172 = 52
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