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ATQ,
Let the maximum marks of the exam be 100x
Sneha’s marks = 0.41 × 100x = 41x
Passing marks = 41x + 17
Rohan’s marks = 0.49 × 100x = 49x
Passing marks = 49x - 7
So, 41x + 17 = 49x - 7
⇒ 8x = 24
⇒ x = 3
Passing marks = 41x + 17 = 41 × 3 + 17 = 123 + 17 = 140
Indicate the numbers that are divisible by both 2 and 3.
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