Question
A person "P" allocates their monthly income as follows:
First, 25% is spent on education. From the remaining amount, 40% is used for food. After that, 20% of what remains is spent on groceries. The gap between the expenses on food and groceries is Rs. 4200. Determine P’s total monthly income.Solution
ATQ;
Education = 25%
Remaining = 75%
Food = 40% of 75% = 30% of total
Left after food = 75% – 30% = 45%
Groceries = 20% of 45% = 9% of total
Difference = Food – Groceries = (30% – 9%) = 21%
If 21% = Rs. 4200
Total income = 4200 × (100 / 21) = Rs. 20000
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
...If √b + (1/√b) = 8, then find the value of b + (1/b).
Solve for x:
3x - 4 = 2x + 5
If a = 2 + √3, then the value of (a6 + a4 + a2 + 1)/a3 is
If x : y : z = 5 : 6 : 8, and (3x + 4z) = 188, then find the value of y.
If x2 – 5x + 1 = 0, then find the value of {x2 + (1/x2)}.
- If (u + v) = 11 and uv = 24, then find the value of (u² + v²).
If √z + (1/√z) = 14, then find the value of z + (1/z).
In a best-of-two chess match between Player X and Player Y, the probability that Player X wins a game is (5/9), and the probability that Player Y loses ...
If p = 33 - q - r and pq + r(q + p) = 260, then find the value of (p² + q² + r²).