Question
A person sells each package of snacks for Rs. 15 each.
On Monday, he sold 80 packages which was 20 more than that on Tuesday but 10 less than that on Wednesday. If he spends 50% of his income earned by selling snack packages on these 3 days, then find his saving in given 3 daysSolution
Number of packages of snack sold on Monday = 80 Number of packages of snack sold on Tuesday = 80 – 20 = 60 Number of packages of snack sold on Wednesday = 80 + 10 = 90 Therefore, his total income of 3 days = (80 + 60 + 90) × 15 = 230 × 15 = Rs. 3450 Therefore, savings of person in given 3 days = 0.50 × 3450 = Rs. 1725
Given a triangle with two sides measuring 12 cm and 16 cm, which of the following cannot be a possible length for the third side?
- Find the remainder on dividing (5x 3  + 4x 2  – 10x + 1) by (2x – 4).
The area (in sq, units) of the triangle formed by the graphs of 8x + 3y = 24, 2x+8 = y and the x – axis is:
If x −y =4and xy =45,thenthevalueof x 3 −y3is:
If x + y = 2 and 1/x + 1/y = 18/15, then find the value of (x3 + y3)?
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
If y + 1/y = 2 then find y117 + 1/(y117)
if a2 + b2 + c2Â =Â 2(4a -5b -9c)-122 , then a-b-c = ?
If a – b – c = 0, then the value of (a2 + b2 + c2)/(b + ac) is:
If 5x - 13xy + 6y = 0, find x : y.