Question
A person sells each package of snacks for Rs. 15 each.
On Monday, he sold 80 packages which was 20 more than that on Tuesday but 10 less than that on Wednesday. If he spends 50% of his income earned by selling snack packages on these 3 days, then find his saving in given 3 daysSolution
Number of packages of snack sold on Monday = 80 Number of packages of snack sold on Tuesday = 80 – 20 = 60 Number of packages of snack sold on Wednesday = 80 + 10 = 90 Therefore, his total income of 3 days = (80 + 60 + 90) × 15 = 230 × 15 = Rs. 3450 Therefore, savings of person in given 3 days = 0.50 × 3450 = Rs. 1725
2Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 19Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 70...
6000 3002 1503 ? 378.75 191.375 97.6875
...If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...8   24    12    ?   18     54
3 ? 7 16 71 346
...104   106   110   113   ?   126
12, 18, 28, 42, 52, ?
18Â Â Â Â Â Â Â Â Â Â Â Â 29 Â Â Â Â Â Â Â Â Â Â Â Â Â Â 51 Â Â Â Â Â Â Â Â 84 Â Â Â Â Â Â Â Â 128 Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 182
5, 8, 17, ?, 37, 48
(32.03 + 111.98) ÷ 18.211 = 89.9 – 20.23% of ?
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