Question
A pear has a cylindrical-shaped seed exactly in the
center. If the diameter and height of the seed are both equal to one-fifth of the diameter of the fruit, then determine the volume of the pulp of the fruit as a percentage of its total volume. {The thickness of the outer covering is negligible}.Solution
ATQ, Let diameter of the Pear fruit = β2dβ cm Diameter/Height of the seed = 2d Γ 1/5 = (2d/5) cm Volume of the seed = Ο(d/5)2(2d/5) = {2Οd3/125} cm3 Volume of the Pear fruit = {(4/3)Ο(d)3} cm3 Required percentage = [{(4/3)Ο(d)3 β 2Οd3/125 }/((4/3)Ο(d)3)] Γ 100 = {(4/3 β 2/125)/(4/3)} Γ 100 = 98.8%
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