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      Question

      A pear has a cylindrical-shaped seed exactly in the

      center. If the diameter and height of the seed are both equal to one-fifth of the diameter of the fruit, then determine the volume of the pulp of the fruit as a percentage of its total volume. {The thickness of the outer covering is negligible}.
      A 98.8% Correct Answer Incorrect Answer
      B 95.8% Correct Answer Incorrect Answer
      C 90.8% Correct Answer Incorrect Answer
      D 65.8% Correct Answer Incorrect Answer
      E none of these Correct Answer Incorrect Answer

      Solution

      ATQ, Let diameter of the Pear fruit = β€˜2d’ cm Diameter/Height of the seed = 2d Γ— 1/5 = (2d/5) cm Volume of the seed = Ο€(d/5)2(2d/5) = {2Ο€d3/125} cm3 Volume of the Pear fruit = {(4/3)Ο€(d)3} cm3 Required percentage = [{(4/3)Ο€(d)3 – 2Ο€d3/125 }/((4/3)Ο€(d)3)] Γ— 100 = {(4/3 – 2/125)/(4/3)} Γ— 100 = 98.8%

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