A pear has a cylindrical-shaped seed exactly in the center. If the diameter and height of the seed are both equal to one-fifth of the diameter of the fruit, then determine the volume of the pulp of the fruit as a percentage of its total volume. {The thickness of the outer covering is negligible}.
ATQ, Let diameter of the Pear fruit = ‘2d’ cm Diameter/Height of the seed = 2d × 1/5 = (2d/5) cm Volume of the seed = π(d/5)2(2d/5) = {2πd3/125} cm3 Volume of the Pear fruit = {(4/3)π(d)3} cm3 Required percentage = [{(4/3)π(d)3 – 2πd3/125 }/((4/3)π(d)3)] × 100 = {(4/3 – 2/125)/(4/3)} × 100 = 98.8%
20 910?2971.5
...Complete the series.
19, 23, 26, 30, 33, ?
If  204    196       223   x  284
Then, what is the average of the numbers of the above series?
...25Â Â Â Â Â Â Â Â Â Â 34Â Â Â Â Â Â Â Â Â Â 61Â Â Â Â Â Â Â Â Â Â 106Â Â Â Â Â Â Â Â 169Â Â Â Â Â Â Â Â ?
...18Â Â Â 19Â Â Â Â 28Â Â Â Â 53Â Â Â 102Â Â Â ?
2187, 1458, 972, ?, 432, 288
Direction: Which of the following will replace ‘?’ in the given question?
342, ‘?’, 420, 462, 506, 552, 60
6Â Â Â Â Â Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â Â Â Â Â Â 24Â Â Â Â Â Â Â Â Â Â Â 218Â Â Â Â Â Â Â Â Â 3486Â Â Â Â Â Â Â 43575
10Â Â Â Â Â Â Â...
The following expressions form a series followed by a (?). Find the odd one out first and then find that what will come in place of the question mark (?...
3 15 35 63 99 ?
