A and B together have total of Rs.6000 out of which they donated 20% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 50% more amount than B. If the amount received by A is Rs.2X, then find the value of [(X/12) + 10].

Statements:

P > O ≥ D > M ≤ Y < L; M > G > Q

Conclusions:

I)  O > Q

II) L < G

Statement: F < G; F ≥ H > I; D ≥ E > G

Conclusion:

I. I ≥ G

II. E ≥ F

Statements: J = N, K < L, M ≥ J, N ≤ K

Conclusion:

I. N ≤ M

II. L > N

Statements: E = L ≤ G < I = H; E ≥ N < A; W ≥ P ≥ M > I

Conclusions:

I. E < W

II. A ≥ M

III. N < P

Statements: V ≥ W > X = Y, C > D = E ≥ V

Conclusions :I. E ≥ W

II. D ≥ Y

III. C > V

Statements:

J < G ≤ T < S = O; W < R > K ≥ F > O

Conclusions:

I).  G < R

II).  S ≥ K

Statements: L ≥ F = Z < P, Q ≥ A > C = P

Conclusions:

I. A > F

II. Q > Z

Statement: D < E < F ≥ G; D ≥ H > I

Conclusion: I. F > I          II. F = I

Statements: M > P > Q < R = T; A < B ≤ C = P; L > N = T > X

Conclusions:

I.   R > P

II.   R < P