Question
A and B together have total of Rs.4500 out of which they
donated 20% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/7) + 21].Solution
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 4500 x 0.8 => 2.4P = 3600 => P = 1500 Share of A = 3600 – 1500 = Rs.2100 So, 3X = 2100 => X = 700 Required value = [(X/7) + 21] = 100 + 21 = 121
More Percentage Questions
- Determine the final value of this expression:
(1/5) of {5⁴ - 24 × 14 + 12 × 18 - 10.5 of 10²} 3% of 842 ÷ 2% of 421 = ?
√225 + 27 × 10 + ? = 320
- Determine the value of ‘p’ if p = √529 + √1444
45 % of 180 + √144 * 8 = ?2 + 70 % of 80
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7?2 = √20.25 × 10 + √16 + 32
- What will come in place of the question mark (?) in the following questions?
(2⁴ + 6²) ÷ 2 = ? 18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
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