A and B together have total of Rs.4500 out of which they donated 20% to the orphanage school. The remaining amount is to be then redistributed between them in such a manner that A gets 40% more amount than B. If the amount received by A is Rs.3X, then find the value of [(X/7) + 21].
Let the amount received by B be Rs.P. Therefore, amount received by A = 1.40 x P = Rs.1.4P According to the question, => (P + 1.4P) = 4500 x 0.8 => 2.4P = 3600 => P = 1500 Share of A = 3600 – 1500 = Rs.2100 So, 3X = 2100 => X = 700 Required value = [(X/7) + 21] = 100 + 21 = 121
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