Question
After increase in the price of coffee by 25%, a person
is able to buy 4 kg less for Rs. 1,640. Find the original and increased price of the coffee per kg.Solution
Let the original price (O.P.) be Rs. x per kg. ∴ New price (N.P.) = 125% of x = Rs. 5x/4 per kg. Quantity of coffee the person could buy at original price = 1640/x kg. Quantity of coffee he can buy at new price = (1640 × 4)/5x = 1312/x kg Given that difference between the quantity at original price and at new price is 4 kg. ∴ 1640/x - 1312/x = 4 ⇒ 328/x = 4 ⇒ = 82 ∴ O.P. = Rs.82 and N.P. = Rs. 5x/4 = (5 × 82)/4 = Rs.102.5
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...3.934 - 124.07 + 35.94 + 12.83 of 4.85 - 84.76 ÷ √26 = ?3
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1680.23 ÷ 27.98) + (600.32 ÷ 23.9) + 1384.11 = ?
What approximate value should replace the question mark?
27.48% of 600.06 + ?% of 200.01 = 284.94
(44.79 × 74.21) ÷ (11.862 – 33.12) + 37.48% of ? = 180.23
2090.03 ÷ 54.98 x 49.9 = ? + 20.32
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
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