Question
After increase in the price of coffee by 25%, a person
is able to buy 4 kg less for Rs. 1,640. Find the original and increased price of the coffee per kg.Solution
Let the original price (O.P.) be Rs. x per kg. ∴ New price (N.P.) = 125% of x = Rs. 5x/4 per kg. Quantity of coffee the person could buy at original price = 1640/x kg. Quantity of coffee he can buy at new price = (1640 × 4)/5x = 1312/x kg Given that difference between the quantity at original price and at new price is 4 kg. ∴ 1640/x - 1312/x = 4 ⇒ 328/x = 4 ⇒ = 82 ∴ O.P. = Rs.82 and N.P. = Rs. 5x/4 = (5 × 82)/4 = Rs.102.5
If tan A = 4/3, 0 ≤ A ≤ 90°, then find the value of sec A.
Find the exact value of cos120°
Find the value of the following:sin(36° + A) × cos(54° – A) + cos(36° + A) × sin(54°–A)
sin2 7˚ + sin2 9˚ + sin2 11˚ + sin2 12˚ + ……… + sin2 83˚ = ?
tan 1˚ × tan 2˚× …………………….tan 88˚ × tan 89˚ = ?
- If secx – tanx = 1/√3, then the value of secx × tanx is:
Suppose 140sin²X + 124cos²X = 136 and 184sin²Y + 200cos²Y = 196, then determine the value of 18cosec²Xsec²Y.
Find the value of the given trigonometric expression:
(sin 22°cos 68° + cos²22°) × sin 30° + (cos 60°tan 45°) × sec 60°
...- If 5tanθ = 12, then find the value of (sinθ – cosθ).
If sec a + tan a = 3, find the value of sin a.