Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 75000 which is 4 times the monthly income of βCβ. If βAβ spends 70% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 20000, then find the savings of βAβ.Solution
Monthly income of βCβ = 75000/4 = Rs. 18750 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (56250 β x) According to the question, 0.30x + 0.20(56250 β x) = 20000 Or, 0.1x = 8750 x = 87500 Or, savings of βAβ = 0.3x = Rs. 26250
A triangle has sides 7 cm, 24 cm, and 25 cm. Determine the largest angle in the triangle.
If logβ(81) = 4/3, find x.
{19.13 2 β 24.86 2 + 84.92% of 501.16} = ?Β
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