Question
The sum of the monthly incomes of ‘A’, ‘B’ and
‘C’ is Rs. 75000 which is 4 times the monthly income of ‘C’. If ‘A’ spends 70% of his income while ‘B’ spends 80% of his income and the sum of their savings is Rs. 20000, then find the savings of ‘A’.Solution
Monthly income of ‘C’ = 75000/4 = Rs. 18750 Let the monthly income of ‘A’ be Rs. x Therefore, monthly income of ‘B’ = Rs. (56250 – x) According to the question, 0.30x + 0.20(56250 – x) = 20000 Or, 0.1x = 8750 x = 87500 Or, savings of ‘A’ = 0.3x = Rs. 26250
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
Find the area between the lines 18x +12y = 108, 9x + 6y = 27, x - axis and y -axis.
If in two linear equations ax + by = c and dx + ey = f and a/d = b/e = c/f then, which of the following is true about the two equations?
For which value of m, there is no solution to the equation -
a – b = 5
ma – 4b = 1
The lines x + y = 9 and x - y = 3 intersect at point P. Find the coordinates of P.
Solve: (x/3) + (x/5) = 16
Find the value of 'a' and 'b' which satisfy the following equations:
9a + 7b = 30
4a - 5b = 62
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
