Question
The sum of the monthly incomes of βAβ, βBβ and
βCβ is Rs. 75000 which is 4 times the monthly income of βCβ. If βAβ spends 70% of his income while βBβ spends 80% of his income and the sum of their savings is Rs. 20000, then find the savings of βAβ.Solution
Monthly income of βCβ = 75000/4 = Rs. 18750 Let the monthly income of βAβ be Rs. x Therefore, monthly income of βBβ = Rs. (56250 β x) According to the question, 0.30x + 0.20(56250 β x) = 20000 Or, 0.1x = 8750 x = 87500 Or, savings of βAβ = 0.3x = Rs. 26250
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