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Let the total number of students in school B be ‘x’. Therefore, total number of students in school A = 1.3x Number of boys in school A = 0.80 × 1.3x = 1.04x Number of boys in school B = 0.65x Required % = [(1.04x – 0.65x)/0.65x] × 100 = 60%
(15 x 6 + 60% of 500 - 16 x 7) = ?
25% of 300 + √(?) = 35% of 600 - 15% of 300
(8 x 9) ÷ 5 + ?2 = 23.4
(22 + √3364)/(? + 4) = 10
(26)2 = {(20% of 40% of 18200) ÷ ?} × 1664 ÷ 128
44% of 560 + 68% of 2160 × 5/12 =? + 32% of 920.
115% of 40 + 3 × 4 = ? × 11 – 8
520% of 360 – 12% of 400 = ? x 4
104 × 21 ÷ 13 + ? % of 300 = 320 + 22