Question
The monthly income of a person is Rs.25000 from which
he spends 20% on rent, 10% of remaining on food and 20% of remaining on clothing. The remaining amount, he shares between his son and daughter in the ratio of 5:4. Find the difference between amount spent on rent and share of his daughter.Solution
Let monthly income be 100x. Spent on rent = 100x × (20/100) = 20x Spent on food = (100x − 20x) × (10/100) = 8x Spent on clothing = (100x − 20x − 8x) × (20/100) = 14.4x Remaining amount = 100x − 20x − 8x − 14.4x = 57.6x Share of son = 57.6x × (5/9) = 32x Share of daughter = 57.6x − 32x = 25.6x Required difference = 25.6x − 20x = 5.6x => 5.6x × (25000/100x)  = Rs. 1400
(1/2) – (3/5) + 3(1/3) = ? + (5/6)
9 × 40 × 242 × 182 = ?2
212.3 × 4414.7 × 4623.4 × 4845.85 = 462?
52% of 400 + √(?) = 60% of 600 - 25% of 400
447.8 × 441.2 ÷ 445 = 44 × 44?
Determine the value of 'p' in following expression:
720 ÷ 9 + 640 ÷ 16 - p = √121 X 5 + 6²- 7What will come in the place of question mark (?) in the given expression?
(? ÷ 16) = (20 ÷ ?) X 20- What will come in the place of question mark (?) in the given expression?
62.5% of 120 + ? = (720 + 90) ÷ √36 - What will come in place of the question mark (?) in the following questions?
25% of 360+40=? 30% of 2200 +’?’ x 50 – 1020 = 11x 306 + (√ 2250 ÷ 0.1) Â
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