Question
An army lost 20% its men in war, 20% of the remaining
due to diseases and 20% of the rest were disabled. Thus, the strength was reduced to 64,000 active men. Find the original strength.Solution
Let the original strength of men in army = x Then, lost in war Rest men = x - (20 × x)/100 = 4x/5 Now, loss of men due to disease, rest men = 4x/5 - 4x/5 × 20/100 = (16 x)/25 Now, after disabled, rest men = (16 x)/25 - (16 x)/25 × 20/100 = (64 x)/125 Now, according to the question, (64 x)/125 = 64,000 x = 1,25,000
2, 9, 19, 32, 48, 67, ?
64Â Â Â 48Â Â Â 36Â Â Â 22Â Â Â Â 16Â Â Â Â 8
?     190      210      238      274     318
...40 41 86 ? 1084 5445
...148, ‘?’ , 15 4 , 17 8 , 23 8 , 35 8 , 56 8
31   48    67    90   ?      150
22, 23, 31, 57, 122, 247
1. In series II, if ‘x’ is the right term, then find which of the following statement(s) are true.
I. x/124 is a factor 6 and 8.
6Â Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â Â 40Â Â Â Â Â Â Â Â Â Â Â 32Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 249Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 240
203, 223, 198, 218, ?, 213
