Question
An army lost 20% its men in war, 20% of the remaining
due to diseases and 20% of the rest were disabled. Thus, the strength was reduced to 64,000 active men. Find the original strength.Solution
Let the original strength of men in army = x Then, lost in war Rest men = x - (20 × x)/100 = 4x/5 Now, loss of men due to disease, rest men = 4x/5 - 4x/5 × 20/100 = (16 x)/25 Now, after disabled, rest men = (16 x)/25 - (16 x)/25 × 20/100 = (64 x)/125 Now, according to the question, (64 x)/125 = 64,000 x = 1,25,000
More Percentage Questions
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â
