Question
A can complete a work in 20 days, B in 30 days and C in
60 days. They started working together. After 4 days, A left the work and B and C completed the remaining work. In how many more days was the remaining work completed?Solution
ATQ, A's 1-day work = 1/20 B's 1-day work = 1/30 C's 1-day work = 1/60 Together, 1-day work = 1/20 + 1/30 + 1/60 = 3/60 + 2/60 + 1/60 = 6/60 = 1/10 Work done in 4 days = 4/10 = 2/5 Remaining work = 1 - 2/5 = 3/5 Now B and C complete the remaining work. B + C 1-day work = 1/30 + 1/60 = 2/60 + 1/60 = 3/60 = 1/20 Time taken = (3/5) ÷ (1/20) = (3/5) × 20 = 12 Hence, the correct answer is 12 days.
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