Question
A can complete a work in 20 days, B in 30 days and C in
60 days. They started working together. After 4 days, A left the work and B and C completed the remaining work. In how many more days was the remaining work completed?Solution
ATQ, A's 1-day work = 1/20 B's 1-day work = 1/30 C's 1-day work = 1/60 Together, 1-day work = 1/20 + 1/30 + 1/60 = 3/60 + 2/60 + 1/60 = 6/60 = 1/10 Work done in 4 days = 4/10 = 2/5 Remaining work = 1 - 2/5 = 3/5 Now B and C complete the remaining work. B + C 1-day work = 1/30 + 1/60 = 2/60 + 1/60 = 3/60 = 1/20 Time taken = (3/5) ÷ (1/20) = (3/5) × 20 = 12 Hence, the correct answer is 12 days.
599.9 - ? + 64.9 = (5% of 300.012) × 10.032
What approximate value will come in place of the question mark (?) in the following question?
(29.98% of 9840) + ? + (19.899% of 8490) = 7560
Determine the simplified value of the given mathematical expression.
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
(80.95) (1/4) + (3.05) 3 - 119.78 × 2.15 + (14.98)2 = ?
(88.931% of 435) + (61.521% of 516) = ?
54.8% of 800 - √(?) = 33.98% of 400 – 12.42% of 300
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
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