Question
‘X’ and ‘Y’ started a business by investing Rs.
7,500 and Rs. 5,000 respectively. ‘x’ months later, they admitted ‘Z’ as a partner who invested Rs. 10,000. If at the end of the year, the profit share of ‘X’ was Rs. 9,000 out of the total profit of Rs. 18,000, then find the value of ‘x’.Solution
Let ‘Z’ invested for ‘m’ months. So,
x = 12 − m Ratio of profit shares of ‘X’, ‘Y’ and ‘Z’
= (7500 × 12) : (5000 × 12) : (10000 × m) = 90 : 60 : 10m ATQ, 9000 / 18000 = 90 / (90 + 60 + 10m) 1 / 2 = 90 / (150 + 10m) 150 + 10m = 180 10m = 30 m = 3 So, x = 12 − 3 = 9
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.
The ratio of roots of an equation
ax²+bx+b = 0 is p : q
Then find, √p/√q + √q/√p + √p/√q ?
I. p2 – 5p + 6 = 0
II. 36q2 = 81
...I. p² - 365 = 364
II. q - √ 529 = √ 169
For given pair of equations, how many solutions are possible?
7x − 3y = 20 and 14x − 5y = 40
If x - √3 y = 8 Find the slope in angle?
If 2x + 3y = 27 and 3x - y = 13, find (x + y).
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