Question
A man invested a certain amount in two schemes, A and B,
in the ratio 3:2. Scheme A offers 12% annual simple interest, and Scheme B offers 10% annual simple interest. After 2 years, the total interest earned from both schemes is ₹3,024. What was the total amount invested?Solution
Let the total amount invested be ₹x. Amount invested in Scheme A = (3/5)x, and in Scheme B = (2/5)x. Interest from Scheme A = [(3/5)x * 12 * 2] / 100 = (72/500)x. Interest from Scheme B = [(2/5)x * 10 * 2] / 100 = (40/500)x. Total interest = (72/500)x + (40/500)x = 112x / 500. Given total interest = ₹3024. 112x / 500 = 3024 x = (3,024 * 500) / 112 = ₹13500 Correct Option: c
18 45 90 235 450 1125 2250
...42, 85, 172, 343, 687, 1375
1, 4, 20, 126, 1026, 10170
79, 152, 231, 314, 405, 500
Find the wrong no in the given number series.
11, 18, 32, 60, 112, 228
Find the wrong number in the given number series.
21, 11, 12, 19, 41, 105
- Find the wrong number in the given number series.
154, 137, 114, 84, 46, 11 - Find the wrong number, in the given number series.
2, 5, 11, 23, 47, 97, 191 23, 36, 53, 69, 95, 124, 155
109 106 101 94 86 74
...