Question
In a factory with 8750 workers, 44% are men, and the
remaining are women. 60% of the men and 45% of the women work as managers, out of which only 160 men and 155 women are not working as managers. What % of the total number of workers in the factory are working as managers?Solution
ATQ, Number of men in the Factory = 8750 × 0.44 = 3850 Number of women in the Factory = 8750 – 3850 = 4900 Number of men who worked as a Manager = 3850 × 0.6 = 2310 Number of women who worked as the manager = 4900 × 0.45 = 2205 Number of men working as a manager = 2310 – 160 = 2150 Number of women working as the manager = 2205 – 155 = 2050 So, total number of workers in the factory working as a manager = 2150 + 2050 = 4200 Therefore, required percentage = (4200/8750) × 100 = 48%
For the ANOVA which of the following options is INCORRECT.
1.      Null hypothesis H0 : μ1 = μ2 = ... = μn
2.      F ...
For the distribution with unknown θ
We set the tes...
The grouped data for the observation are as follows.
Class :Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â 2-4Â Â Â Â Â Â Â Â 4-6Â Â Â Â Â Â Â Â Â 6-8<...
If ten coins are tossed simultaneously, then the probability of getting at most I head is:
If mean and mode of the distribution is 32 and 21, then the distribution:
For making frequency distribution, the number of classes used depends upon:
Which one is parameter from population?
The mean and median of the distribution are 10 and 11 respectively, then the mode equals to
The deseasonalised time - series data will have only trend (T), cyclical (C) and irregular (I) components and is expressed as:
If xi | fi , i = 1,2,...n is a frequency distribution with standard deviation 15 and mean 30, the coefficient of variation will be equal to:
