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      Question

      Product of two consecutive positive even numbers is

      120. Find the sum of the digits of the two numbers.┬а
      A 4 Correct Answer Incorrect Answer
      B 6 Correct Answer Incorrect Answer
      C 8 Correct Answer Incorrect Answer
      D 10 Correct Answer Incorrect Answer

      Solution

      Let the numbers be ( 2n ) and ( (2n + 2) ) respectively.┬а ATQ,┬а (2n * (2n + 2) = 120 )┬а Or, ( n * (2n + 2) = 60 )┬а Or, ( 2n┬▓ + 2n = 60 )┬а Or, ( n┬▓ + n = 30 )┬а Or, ( n┬▓ + n - 30 = 0 )┬а Or, ( n┬▓ + 6n - 5n - 30 = 0 )┬а Or, ( n(n + 6) - 5(n + 6) = 0 )┬а Or, ( (n + 6)(n - 5) = 0 )┬а So, ( n = -6 ) or ( 5 )┬а So, (n = 5)┬а So, numbers are ( 10 ) and ( 12 ).┬а Therefore, required sum = ( 1 + 0 + 1 + 2 = 4 )┬а

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