Question
Find the sum of digits of the greatest three-digit
number which leaves a remainder of 5 when divided by 8, 9 and 12.Solution
ATQ, LCM of (8, 9 and 12) = 72 Largest 3-digit number divisible by 72 = 72 × 13 = 936 So, N = 936 + 5 = 941 Sum of digits of 'N' = 9 + 4 + 1 = 14
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