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      Question

      Find the sum of digits of the greatest three-digit

      number which leaves a remainder of 5 when divided by 8, 9 and 12.
      A 20 Correct Answer Incorrect Answer
      B 28 Correct Answer Incorrect Answer
      C 14 Correct Answer Incorrect Answer
      D 36 Correct Answer Incorrect Answer

      Solution

      ATQ, LCM of (8, 9 and 12) = 72 Largest 3-digit number divisible by 72 = 72 Γ— 13 = 936 So, N = 936 + 5 = 941 Sum of digits of 'N' = 9 + 4 + 1 = 14

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