If a number is decreased by 8 and divided by 12, the result is 16. What would be the result if 10 is subtracted from the number and then it is divided by 5.
Let the number be x. According to the question, (x-8)/12 = 16 x – 8 = 192 , x = 200 Now, ∴ Required resultant = (x-10)/5 = (200-10)/5 = 190/5 = 38
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If log 2 = 0.3210 and log 3 = 0.4661, the value of log5 1024 is:
