Question
When the digits of a two-digit number are interchanged,
the new number becomes 11 more than 120% of the original number. If the sum of the digits is 8, find the original number.Solution
Let the unit digit and tens digit of the original number be ‘y’ and ‘x’, respectively.
Original number = (10x + y)
According to the data given:Â
10y + x = 1.2 × (10x + y) + 11
Multiplying both sides by 5,Â
50y + 5x = 60x + 6y + 55Â
⇒ 55x − 44y = −55 …. (I)
And, x + y = 8 …. (II)
From (II), x = 8 − y. Substitute in (I):Â
55(8 − y) − 44y = −55Â
440 − 99y = −55Â
99y = 495Â
y = 5
Then x = 8 − 5 = 3.Â
So, original number = (10 × 3 + 5) = 35.
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