Question
When the digits of a two-digit number are interchanged,
the new number becomes 39 less than 150% of the original number. If the sum of the digits is 6, find the original number.Solution
Let the unit digit and tens digit of the original number be ‘y’ and ‘x’, respectively.
Original number = (10x + y)
According to the data given:Â
10y + x = 1.5 × (10x + y) − 39
Multiplying both sides by 2,Â
20y + 2x = 30x + 3y − 78Â
⇒ 28x − 17y = 78 …. (I)
And, x + y = 6 …. (II)
From (II), x = 6 − y. Substitute in (I):Â
28(6 − y) − 17y = 78Â
168 − 45y = 78Â
45y = 90Â
y = 2
Then x = 6 − 2 = 4.Â
So, original number = 10 × 4 + 2 = 42.
√256 * 3 – 15% of 300 + ? = 150% of 160
(5.6 + 2.4 + 13.8 – 2.8) × 5 = ? × (12.5 – 7.5)
Solve: 3/4÷2/3 ​
(292 – 141) ÷ 5 + (40 ÷ 2) + 23 = ?
(26)2 = {(20% of 40% of 18200) ÷ ?} × 1664 ÷ 128Â
- What will come in place of (?) in the given expression.
(18.5 × 2) + (3.5 × 4) = ? What will come in the place of question mark (?) in the given expression?
48 X 2.5 + 20% of 150 = ? + 166
166/? = √576 - 3.25
[(36 × 15 ÷ 96 + 19 ÷ 8) × 38] = ?% of 608