Question
Find the sum of all the numbers between 100 and 800,
which are divisible by 6, 8 and 10.Solution
LCM of 6, 8 and 10 = 120 So, desired numbers are: 120, 240, …, 720 Number of terms = (720 – 120)/120 + 1 = 6 Sum = (6/2) × [120 + 720] = 2520
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