Question
Find the sum of all the numbers between 100 and 800,
which are divisible by 6, 8 and 10.Solution
LCM of 6, 8 and 10 = 120 So, desired numbers are: 120, 240, …, 720 Number of terms = (720 – 120)/120 + 1 = 6 Sum = (6/2) × [120 + 720] = 2520
More No. System Questions
√3600% of 150 + 3/5 of 360 - ? = 210
52% of 36% of 810 = 72% of 18% of ?
315 ÷ 9 + 23 × 3+ 22 = ?× √441
(560 ÷ 32) × (720 ÷ 48) = ?
What value should come in the place of (?) in the following questions?
30% of 160 – 25% of 240 + 43 = ?
√0.49 + √6.25 + √1.44 + √1.21 =? % of 125
31% of 1900 - ? = 73
4.5 times 5/0.9× 35% of 240 =?
√? = 80% of 720 - 22% of 2500
{(81% of 800 + 28 × 4) – 27 × ?} = 11 × 20
