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    Question

    Find the sum of all the numbers between 100 and 800,

    which are divisible by 6, 8 and 10.
    A 2000 Correct Answer Incorrect Answer
    B 4800 Correct Answer Incorrect Answer
    C 2520 Correct Answer Incorrect Answer
    D 1800 Correct Answer Incorrect Answer

    Solution

    LCM of 6, 8 and 10 = 120 So, desired numbers are: 120, 240, …, 720 Number of terms = (720 – 120)/120 + 1 = 6 Sum = (6/2) Γ— [120 + 720] = 2520

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