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    Question

    The biggest three-digit number leaves 2 as a remainder when

    divided by 11, 9, and 4. What is the sum of its digits?
    A 24 Correct Answer Incorrect Answer
    B 20 Correct Answer Incorrect Answer
    C 28 Correct Answer Incorrect Answer
    D 12 Correct Answer Incorrect Answer

    Solution

    ATQ,

    LCM of (11, 9, and 4) = 396

    Largest 3-digit number divisible by 396 = 396 × 2 = 792

    So, N = 792 + 2 = 794

    Sum of digits of 'N' = 7 + 9 + 4 = 20

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