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    Question

    The smallest positive integer 'R' which when divided by 9,

    18, and 27 leaves 6 as the remainder in each case. Find the value of ('7R' - 20).
    A 485 Correct Answer Incorrect Answer
    B 400 Correct Answer Incorrect Answer
    C 375 Correct Answer Incorrect Answer
    D 515 Correct Answer Incorrect Answer

    Solution

    ATQ,

    As we know the least number which is divisible by 'a', 'b', and 'c' is the LCM of 'a', 'b', and 'c'.

    So, the number which is completely divisible by 9, 18, and 27 = LCM of 9,

    18, and 27 = 54

    So, 'R' = 54 + 6 = 60

    Now,

    (7R - 20) = (60 × 7) - 20 = 420 - 20 = 400

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