Question
The smallest positive integer 'R' which when divided by 9,
18, and 27 leaves 6 as the remainder in each case. Find the value of ('7R' - 20).Solution
ATQ,
As we know the least number which is divisible by 'a', 'b', and 'c' is the LCM of 'a', 'b', and 'c'.
So, the number which is completely divisible by 9, 18, and 27 = LCM of 9,
18, and 27 = 54
So, 'R' = 54 + 6 = 60
Now,
(7R - 20) = (60 × 7) - 20 = 420 - 20 = 400
elude
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