Question
Suppose '68472m' is divisible by 6 but not divisible by 5. Find the value of (m × 3 - 2).
Solution
ATQ,
Sum of digits = 6 + 8 + 4 + 7 + 2 + m = 27 + m
We need (27 + m) divisible by 3, and m even (not 0 or 5).
Try m = 6 → 27 + 6 = 33
So, m = 6
(m×3 - 2) = 18 - 2 = 16
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