Question
‘N’ be the highest 3-digit number which leaves a
remainder of 3 when divided by 4, 6, and 9. What is the least number that must be added to ‘N’ to make it a perfect square?Solution
ATQ,
LCM (4, 6, 9) = 36
Highest 3-digit number divisible by 36 = 36 × 27 = 972
So, N = 972 + 3 = 975
Next perfect square after 975 is 32² = 1024
Required number = 1024 - 975 = 49
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