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      Question

      If the number 8357pt is divisible by 15, how many values

      can 'p' take?
      A 12 Correct Answer Incorrect Answer
      B 10 Correct Answer Incorrect Answer
      C 6 Correct Answer Incorrect Answer
      D 2 Correct Answer Incorrect Answer

      Solution

      ATQ,

      Divisible by 15 β‡’ divisible by both 5 and 3

      Divisible by 5 β‡’ t = 0 or 5

      Divisible by 3 β‡’ sum divisible by 3

      Case 1: t = 0

      Sum = 8 + 3 + 5 + 7 + p + 0 = p + 23

      Divisible by 3 β‡’ p = 1, 4, 7

      Case 2: t = 5

      Sum = 8 + 3 + 5 + 7 + p + 5 = p + 28

      Divisible by 3 β‡’ p = 2, 5, 8

      Total values of p: 3 + 3 = 6 values

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