Question
A number when divided by 21 gives a remainder of 7. What
would be the remainder when six times the number is divided by 21?Solution
ATQ,
Let the number be:
Number = 21E + 7, where E is an integer.
Six times the number = 6 × (21E + 7) = 126E + 42
Now divide by 21:
(126E + 42) = (126E + 21 + 21)
⇒ Remainder = 0
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